bank angle
#21
On Reserve
Joined APC: Mar 2009
Posts: 19
Just my opinion
I dont think youre wrong with what you're saying, it's just seemed to text book like.
#22
Line Holder
Joined APC: Feb 2007
Posts: 40
As you're rolling the aircraft and increasing the horizontal component of lift are you not in turn reducing the VCL and therefore requiring more back pressure to create more lift and maintain level? So as I roll the airplane into a steep turn I have to increase back pressure, accelerating the aircraft. Even if its only slight accelerations, until reaching the desired bank, you are accelerating. So at high enough speeds slight accelerations could impose a load. There really is no such thing as a perfectly level turn, and you cant initiate a roll without acclerating the aircraft to achieve a higher AOA and maintain level.
Just my opinion
I dont think youre wrong with what you're saying, it's just seemed to text book like.
Just my opinion
I dont think youre wrong with what you're saying, it's just seemed to text book like.
#23
Gets Weekends Off
Joined APC: Jun 2009
Posts: 317
The point is, Va is directly related to angular acceleration. You can bank the aircraft without having angular acceleration.
Brian: Angular acceleration is a biproduct of pressures on the elevator. For instance, a loop is nothing more than back pressure that causes and angular acceleration. To link it all together consider this: back pressure causes angular acceleration, angular acceleration results in g-forces.
Hope this helps you guys, I am a few drinks in tonight, so much for recovery Sundays! Cheers!
#24
Line Holder
Joined APC: Sep 2009
Position: E-175 FO
Posts: 72
Not necessarily. With the wings unloaded, bank angle is irrelevant. You can be at 90 degrees with no horizontal component of lift, with the vertical component of lift being produced entirely by the fuselage.
When referring to to maneuvering flight, "horizontal component of lift" and "vertical component of lift" are a bit simplistic.
So as I roll the airplane into a steep turn I have to increase back pressure, accelerating the aircraft.
I really do think it would behoove everyone to have a little bit of acro under their belt.. I'm often a bit confused by how people see the mechanics of maneuvering flight. I almost think we "simplify" things so much when teaching aerodynamics that we re-complicate them--but convey an essential misunderstanding of their nature.
~Fox
#25
On Reserve
Joined APC: Dec 2009
Posts: 15
I'll start with a definition then my .02
Per the PHAN "Any force applied to an aircraft to deflect its flight from a straight line produces a stress on its structure, and the amount of this force is the load factor."
Here are my personal thoughts on what's going on when the aircraft is descending in a turn:
An aircraft turning is not moving in a straight line therefore a positive load is placed on the wings. The "straight line" is constantly changing resulting in constant acceleration. But why does the load only seem to be experienced when altitude is maintained? Is it the altitude or bank that is producing the load? It is the bank - here is why-
When the aircraft's flight path is changed downward in a turn, a negative load is induced on the aircraft. Conveniently, the loss of vertical lift aids in decreasing the altitude so if the pilot decides not to adjust attitude at all in a turn, the aircraft will descend naturally. This will help to decrease the positive load factor from the wings.
The canceling effects of these two loads will only be experienced momentarily. Once the aircraft is stabilized in a downward flight path, the negative load factor will diminish however the positive load from the wings will not be cancelled out anymore.
In essence, maintaining altitude is not what produces the positive load, the turn causes the positive load... It just so happens that a downward pitch has the reverse effect on load factor which cancels out the effects of the load factor from the turn.
Per the PHAN "Any force applied to an aircraft to deflect its flight from a straight line produces a stress on its structure, and the amount of this force is the load factor."
Here are my personal thoughts on what's going on when the aircraft is descending in a turn:
An aircraft turning is not moving in a straight line therefore a positive load is placed on the wings. The "straight line" is constantly changing resulting in constant acceleration. But why does the load only seem to be experienced when altitude is maintained? Is it the altitude or bank that is producing the load? It is the bank - here is why-
When the aircraft's flight path is changed downward in a turn, a negative load is induced on the aircraft. Conveniently, the loss of vertical lift aids in decreasing the altitude so if the pilot decides not to adjust attitude at all in a turn, the aircraft will descend naturally. This will help to decrease the positive load factor from the wings.
The canceling effects of these two loads will only be experienced momentarily. Once the aircraft is stabilized in a downward flight path, the negative load factor will diminish however the positive load from the wings will not be cancelled out anymore.
In essence, maintaining altitude is not what produces the positive load, the turn causes the positive load... It just so happens that a downward pitch has the reverse effect on load factor which cancels out the effects of the load factor from the turn.
#26
On Reserve
Joined APC: Mar 2009
Posts: 19
Sorry I didnt even read the knife edge part, I tend to overlook things in parenthesis.
I was referring more to the original question bellow even though I quoted you on that one hahaha.
Now I'm assuming the original poster wasn't planning on doing knife edge flight, but I could be wrong since he only said bank.
But in a scenario where a pilot enters into a steep level turn there would be that angular acceleration, correct?
So back to your original post:
How can a 60 degree bank level turn be initiated and maintained without there ever being any acceleration? If you do that at VNE the slightest accel. could over stress the plane.
I was referring more to the original question bellow even though I quoted you on that one hahaha.
I was wondering is it safe to roll into a 60 or 70 degree bank in a cessna 152 or 172?
But in a scenario where a pilot enters into a steep level turn there would be that angular acceleration, correct?
So back to your original post:
How can a 60 degree bank level turn be initiated and maintained without there ever being any acceleration? If you do that at VNE the slightest accel. could over stress the plane.
#27
Gets Weekends Off
Joined APC: Jun 2007
Posts: 348
Sorry I didnt even read the knife edge part, I tend to overlook things in parenthesis.
I was referring more to the original question bellow even though I quoted you on that one hahaha. Now I'm assuming the original poster wasn't planning on doing knife edge flight, but I could be wrong since he only said bank.
But in a scenario where a pilot enters into a steep level turn there would be that angular acceleration, correct?
So back to your original post:
How can a 60 degree bank level turn be initiated and maintained without there ever being any acceleration? If you do that at VNE the slightest accel. could over stress the plane.
I was referring more to the original question bellow even though I quoted you on that one hahaha. Now I'm assuming the original poster wasn't planning on doing knife edge flight, but I could be wrong since he only said bank.
But in a scenario where a pilot enters into a steep level turn there would be that angular acceleration, correct?
So back to your original post:
How can a 60 degree bank level turn be initiated and maintained without there ever being any acceleration? If you do that at VNE the slightest accel. could over stress the plane.
Rolling into a 60 degree level turn will not itself overstress the aircraft, no matter the airspeed. Now, if you do it with full aileron deflection at Vne, we might have some problems, but we're not talking about that. At Vne, you could roll into a normal steep turn, and never exceed any limitation of the aircraft, not any more than you would at Va.
Think of sitting on an airliner going several hundreds of knots rolling into a 30 degree turn. You don't feel any more acceleration than you do in a 152 going 80 knots rolling into a 30 degree turn. The difference shows up in the turn rate. The airliner is going to turn at a degree or two per second (estimated), the 152 several degrees per second.
#28
Gets Weekends Off
Joined APC: Jun 2009
Posts: 317
Gestrich: I am totally lost, why are we descending? What scenario are you trying to introduce? What is the goal of introducing this scenario?
It is neither the bank nor the altitude that induces load, in essence, they are irrelevant. Load is produced, as previously mentioned, by angular acceleration (not to be confused with a turn, bank, or altitude). Instead, it is the direct result of forward or aft pressure on the yoke.
Watchyouralt: I suggest you go back and reread then. As you asked, "without there ever being any acceleration," cleverly in bold I might add. That has been answered at least twice in previous posts, by me and another poster.
I would also ask, what acceleration are you referring to and how do you suspect it would happen? From your wording I am assuming you mean an increase in speed?
#29
I'll start with a definition then my .02
Per the PHAN "Any force applied to an aircraft to deflect its flight from a straight line produces a stress on its structure, and the amount of this force is the load factor."
Here are my personal thoughts on what's going on when the aircraft is descending in a turn:
An aircraft turning is not moving in a straight line therefore a positive load is placed on the wings. The "straight line" is constantly changing resulting in constant acceleration. But why does the load only seem to be experienced when altitude is maintained? Is it the altitude or bank that is producing the load? It is the bank - here is why-
In essence, maintaining altitude is not what produces the positive load, the turn causes the positive load... It just so happens that a downward pitch has the reverse effect on load factor which cancels out the effects of the load factor from the turn.
Per the PHAN "Any force applied to an aircraft to deflect its flight from a straight line produces a stress on its structure, and the amount of this force is the load factor."
Here are my personal thoughts on what's going on when the aircraft is descending in a turn:
An aircraft turning is not moving in a straight line therefore a positive load is placed on the wings. The "straight line" is constantly changing resulting in constant acceleration. But why does the load only seem to be experienced when altitude is maintained? Is it the altitude or bank that is producing the load? It is the bank - here is why-
In essence, maintaining altitude is not what produces the positive load, the turn causes the positive load... It just so happens that a downward pitch has the reverse effect on load factor which cancels out the effects of the load factor from the turn.
getrich is correct in saying that when we bank (just bank, no mx altitude), an acceleration is taking place with regard to displacing the aircraft from a straight line thus some load is being imposed on the aircraft however, this acceleration /load is (more or less) a lateral (transverse) load, not a positive/negative wing load. If you are sitting in the airplane as it rolls, lift still goes straight up however, gravity still pulls toward Earth which is now to you left or right (which ever way you are banked). This means that gravity instead of simply pulling straight down, is now pulling the aircraft to the side which is loading the airplane in the lateral (transverse) direction (much like simply stepping on the rudder in level flight would do, just not so drastic). So, finally, getrich is right, the act of banking period does, itself, impose a load/acceleration on the airplane.
That said, When the FAA/PHAK talk about turns and load factor, they are referring to positive/negative wing loading. With respect to turns, the only loading that the FAA / PHAK / Va / over-stressing the wings are concerned with are positive/negative G loading and if the pilot rolls into a 60 degree bank without maintaining altitude, there is no additional lift being produced by the wings therefore, no additional load is being produced (REMEMBER Positive Wing loading ONLY is of interest here, not lateral load)
The lateral load caused by the bank itself is insignificant with respect to over stressing the aircraft. Think of lateral load like a slip. There is no limitation to my knowledge of a max speed where you can slip an airplane (using max rudder = max lateral force) therefore regardless of speed, there is no real chance of damaging the airplane via lateral acceleration short of knife edge flight into the ground
When we maintain altitude during a 60 degree bank turn, we increase the amount of lift produced by the wing therefore, we induce additional positive wing load. This is the load of interest when we are talking about the load factor experienced in a turn and this is the load where Va comes in.
More or less my $0.02. (more like $0.15)
Listening to myself type is fun
#30
Gets Weekends Off
Joined APC: Jun 2009
Posts: 317
Without the application of rudder, making the flight uncoordinated, there is and never will be a lateral load. If this helps, consider that the inclinometer (ball) is designed to show the pilot when a lateral load is introduced.
A lateral load can only be introduced with application of the rudder or some outside force. An aircraft in knife edge, is therefore, experiencing a 1G lateral load, since weight is supported by this lateral lift.
There is no limitation to my knowledge of a max speed where you can slip an airplane (using max rudder = max lateral force) therefore regardless of speed
Let's take this slightly further, recall a knife edge is 1G lateral load. Assume an aircraft is capable of flying at Vne in knife edge, highly unlike, but let's assume. Even at Vne, in knife edge, they still only have 1G, just like level flight at Vne produces a 1G load on the wings.
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