ISA Temperature & ISA Deviation
I was browsing so site and youtube to understand the PA, DA or ISA Temps Deviation.
Then I got this formula: Pressure Alt= Elevation + (1013 - QNH) x 30 ISA Temp = 15 - (2 x Elevation/Altitude/1000) After than i have browsed some website for online test to do some practice and solve some question and I got all good but saw a some question on a forum that i try to solve with question with answer but when i tried to do my answer is not same as their answer. Example: What is the ISA Temperature & ISA Deviation if the height is 37,000 feet & is -45 degrees ? (Ans: -57 degrees for ISA temperature & +12 for ISA deviation) I used the formula : ISA Temp = 15 - (2 x Elevation/Altitude/1000) ISA Temp = 15 - (2 x 37000/1000) ISA Temp = 15 - (2 x 37) = -59 degress ISA deviation= -45 - -59 ISA deviation= -45 + 59 = +14 degrees How he get -57 for Isa Temp and +12 for deviation ? Example 2: What is the ISA Temperature & ISA Deviation if the height is 57,000 feet & is -67 degrees ? (His Ans: -57 degrees for ISA temperature & -10 for ISA deviation) ISA Temp = 15 - (2 x 57000/1000) ISA Temp = 15 - (2 x 57) = -99degrees ISA deviation= -67 - -99 ISA deviation= -67 + 99 = +32degrees How he get -57 for Isa Temp and -10 for ISA deviation ? The explanation there for Example 1 is: In the ISA the tropopause is at 36000 feet, where the temperature is 56.25 degrees Celsius (or approximately 57). Above the tropopause the temperature remains constant. So at 37000 feet the ISA temperature is approximately 57 degrees Celsius. ISA deviation = Actual Temp ISA temp So if actual temp = -45 at 37000 feet then: ISA deviation = -45 (-57) = +12 The explanation there for Example 2 is: (Ans: -57 degrees for ISA temperature & -10 for ISA deviation) In the ISA the tropopause is at 36000 feet, where the temperature is 56.25 degrees Celsius (or approximately 57). Above the tropopause the temperature remains constant. So at 37000 feet the ISA temperature is approximately 57 degrees Celsius. ISA deviation = Actual Temp ISA temp So if actual temp = -67 at 36000 feet then: ISA deviation = -67 (-57) = -10 But still confuse since the explanation is based on 2 altitude that i don't know how they get it. Thank for help. BTW am learning the theory for PPL just got an ideas before I go to do my PPL since I will have to go to south africa and time is money so I start to understand before going :) |
My question
My first question how do he get -57 for Isa Temp and +12 for deviation ? following their explaination above
From what i had understand on the web the temperation from 38 000 ft to 65,500 feet is constant. My second question is that mean that from 38 000 ft to 65 000ft we don't need to calculate Isa temperation since it is the same -57 degree ? |
The standard atmosphere is -56.5C at 36,000, then the lapse rate is 0, as, by definition, one is in the stratosphere where the temp remains constant.
GF |
One of the things that might be confusing the OP is that the Tropopause is that it does change height. The STANDARD ATMOSPHERE MODEL shows the Trop at around 36000ft. In actuality it changes:
The tropopause height does not gradually drop from low to high latitudes. Rather, it drops rapidly in the area of the subtropical and polar front jets (STJ and PFJ respectively in the Figure on the left), as shown in the Palmen-Newton model of the general circulation (Fig 12.16 or Fig on left). Especially when the jet is strong and the associated front at low levels intense, then the tropopause height drops suddenly across the jet stream. Sometimes the tropopause actually folds down to 500 hPa (5.5 km) and even lower, just behind a well-defined cold front. The subsided stratospheric air within such a tropopause fold (or in the less pronounced tropopause dip) is much warmer than the tropospheric air it replaces, at the same level, and this warm advection aloft (around 300 hPa) largely explains the movement of the frontal low (at the surface) into the cold airmass, a process called occlusion. The height of the tropopause So, the apparent problem of the Trop layer being static should not be assumed. Use the formula and forget the standard trop level. It's like the 15 Deg. C / 59 F value. An assumed standard only, used for the basis of reference, not an in-fact condition most of the time. |
For academic problems, unless otherwise stated, assume the lapse rate stops lapsing at 36,000 and -57* C.
In the real world, that will rarely be the case. But any airliner that can fly that high will do all the math for you. |
Originally Posted by rickair7777
(Post 2533500)
For academic problems, unless otherwise stated, assume the lapse rate stops lapsing at 36,000 and -57* C.
In the real world, that will rarely be the case. But any airliner that can fly that high will do all the math for you. |
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