Here's the way I see it ...

(yes, it's possible I have too much time on my hands and I'm bored?)

According to the clock at the bottom of the video ...

:13 seconds - gear starts down
:52 seconds - tire smoke (runway contact)

If we assume 140KIAS (typical DC-10 landing speed), that equals 236 feet/sec (no wind).

236fps x 39 seconds = 9204'

9204' / 5280 feet per mile = 1.74 miles

1.74 miles x 300 feet per mile (typical 3 degree approach) = 523'

I would call that a typical (IAW SOP) visual approach

Now ... what was the OP's question?

MM