Originally Posted by
Flycameron
KTAS= 300. Aircraft is going to teardrop outbound on the 060 radial and wants to roll inbound on the 100 radial. If the aircraft must start the turn at 20 DME, what constant bank angle will roll you out on the 100 radial?
Does anyone have a good rule of thumb for determining this problem?
Hmm, haven't seen any shortcuts for that one. It's basically a two-part problem, solving for diameter of turn and then using turn radius formula to derive bank angle. First part is easy to do mentally, using 60-to-1 rule at 20DME a difference of 40 degrees is 40/3= ~13.3NM. Second part would be tricky without a scientific calculator, but the turn radius formula is R = V^2 / 11.26*tan(bank), with radius in feet, and V in knots. A 13.3nm diameter turn has a radius of 39,900 feet, so...
39,900 = 90,000 / 11.26*tan(bank)
I come up with about an 11.5 degree bank.
//hoping I didn't just embarrass myself with math in public...