Originally Posted by
Flycameron
KTAS= 300. Aircraft is going to teardrop outbound on the 060 radial and wants to roll inbound on the 100 radial. If the aircraft must start the turn at 20 DME, what constant bank angle will roll you out on the 100 radial?
Does anyone have a good rule of thumb for determining this problem?
Turn radius for a 30 degree bank angle ~ mach minus 2 or 10% of Ground Speed. Roughly double that for 15 degrees. So, 3nm turn for 30 degrees at 300Kts (actual math formula is closer to 2.5, but you asked for ROT), 6 for 15 (again, closer to 5).
60:1 as described in earlier post tells us rough diameter of turn is 13.3NM, so turn radius is about 7 (6.7, but rounded up because you're making a 220 degree turn and I have 7 fingers I can count, but have a tough time counting 6.7).
So my ballpark guess using that ROT would be a bit less than 15 degrees.
Looks like the calculation above says the same.
BTW, if you find yourself spending this much time on any of the questions in the knowledge test, I suggest you're doing it wrong.