Need help to understand a formula
01-27-2018, 05:47 AM
#1
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Joined APC: Jan 2018
Posts: 4
Need help to understand a formula
Hello,
Am Lowell and I will soon go to a flight school for my PPL. But am learning the theoey and try to understand thing before I attend my class.
I found a question and an answer but I would like to know how they get this answer.
Q. Aircraft heading 355 true.variation 7 degree W.Drift 5 degree port.To obey the quadrantal rule.what altitude must you fly?
A. 6500ft
My question how they get it ?
Thank in advance
Am Lowell and I will soon go to a flight school for my PPL. But am learning the theoey and try to understand thing before I attend my class.
I found a question and an answer but I would like to know how they get this answer.
Q. Aircraft heading 355 true.variation 7 degree W.Drift 5 degree port.To obey the quadrantal rule.what altitude must you fly?
A. 6500ft
My question how they get it ?
Thank in advance
01-27-2018, 06:05 AM
#2
Gets Weekends Off
Joined APC: Aug 2007
Position: I pilot
Posts: 2,049
What country still uses the Quadrantal rule? UK CAA switched to the semi circular rule in 2015.
Anyhow, West is best. 355+7
Drift of 5 degrees port, which means left, so subtract 5
355+7-5=357° track, so you would fly an even flight number + 500ft according to the quadrantal rule.
Anyhow, West is best. 355+7
Drift of 5 degrees port, which means left, so subtract 5
355+7-5=357° track, so you would fly an even flight number + 500ft according to the quadrantal rule.
01-27-2018, 06:08 AM
#3
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Joined APC: Jan 2006
Position: Engines Turn Or People Swim
Posts: 39,275
The rule is based on course (track over ground), not heading.
Compass says 355*
Variation of 7* W means actual mag heading is 002*
Port = Left. So the 5* drift to port means you have a wind from the right (East) which is pushing the airplane left (West) by 5*.
So Magnetic Heading of 002* minus left drift of 5* = 357* track over ground which is a (barely) westerly course. So even altitude (+500 for VFR) applies.
Compass says 355*
Variation of 7* W means actual mag heading is 002*
Port = Left. So the 5* drift to port means you have a wind from the right (East) which is pushing the airplane left (West) by 5*.
So Magnetic Heading of 002* minus left drift of 5* = 357* track over ground which is a (barely) westerly course. So even altitude (+500 for VFR) applies.
01-27-2018, 06:18 AM
#4
Gets Weekends Off
Joined APC: Aug 2007
Position: I pilot
Posts: 2,049
Originally Posted by rickair7777
So even altitude (+500 for VFR) applies.
I suggest to the OP that he not get ahead of himself and to also get some current material.
01-29-2018, 01:29 AM
#7
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Joined APC: Jan 2018
Posts: 4
Thank
Thank everyone for help. I saw that question and i wanted to know how they get that since in the example paper they didn't specify the country. there were some question that was refered to singapore and other UK and US. So was a bit mix
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