Jepps..... pitfalls...

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10-13-2006 | 10:37 PM

schone

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Jepps..... pitfalls...

Ladies and Gents,

Need your help in figuring out some stuff. Most of the regionals like to conduct a tech interview which involves in part the jepp/IFR knowledge stuff.

I would appreciate if some of you pps can take the time and outline some of those more trickier questions, one might be asked on an interview with regards to the above mentioned topic/criteria?

I know my jepps pretty darn good and am pretty sharp on my IFR stuff, but am looking for the more trickier questions in the book you might have encountered, either on an interview or with a smart D.E... doesn't matter. Share share share.... we could all benefit, i'm sure.

Thanks
-schone

10-13-2006 | 11:03 PM

CL65driver

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From: I am the Captain now...

XJT asked a few questions about some Jepps for a Mexican airport. Then asked a question about a transition alititude on a DP... they're not always 18,000'. Make sure to read ALL the little notes everywhere on the plate. Attention to detail with these buggers is important.

Oh... and if there's no FAF dictated by the maltese cross, call it a Final Approach Point... atleast that's what my interviewer wanted to hear.

Overall, go to Jeppesen's website and conjure up the whole Chart Clinic they had running a while back. Study that stuff, it will jog your memory on stuff you thought you remembered well... and get you up to speed on the intricacies of things you might have forgotten. Plus, it's a very interesting read!

Good luck job hunting!!!

10-14-2006 | 04:32 AM

FlaZoomie

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From: Lear & EMB-145

Goto http://www.jeppesen.com/wlcs/index.j...ntent=ifr.html

for the chart clinic.

10-14-2006 | 04:45 AM

hatetobreakit2u

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From: FO dhc-6

whas the formula for a VDP?

10-14-2006 | 05:01 AM

SlvShpDrvr

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vdp

timing based: take first 2 digits of HAT and subtract from time inbound
DME based: HAT divided by 300, work from end of rwy

10-14-2006 | 06:27 AM

freezingflyboy

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From: 7ER B...whatever that means.

I was handed a departure procedure with a DME arc and then asked what the total distance the airplane would fly from the first fix after the runway, along the arc and then out to another fix. That one threw me for a loop

10-14-2006 | 09:05 PM

schone

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Quote:

Originally Posted by freezingflyboy

What was the correct way to figure it out? Or did you just use the "direct from XXX apt to XXXXX wpt - XX NM" lines that jepp provides on some of the DPs/STARs?

Thanks!
-schone

10-14-2006 | 10:24 PM

tomgoodman

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From: 767A (Ret)

DME arc length

Quote:

Originally Posted by schone

What was the correct way to figure it out? Or did you just use the "direct from XXX apt to XXXXX wpt - XX NM" lines that jepp provides on some of the DPs/STARs?

If it's not on the plate and you HAVE to calculate an arc segment length, it's 2 x "pi" x R x D divided by 360, where R is the radius of the arc and D is the number of degrees between the starting and ending radials. For example, the 15 DME arc from the 080 to the 140 radial would be 2 x 3.14 x 15 x 60 divided by 360 = 15.7 miles.

Caution: It's been 40 years since I took trigonometry, and even if my answer is correct, giving it in an interview might sound the "nerd alert"!

Last edited by tomgoodman; 10-15-2006 at 05:29 AM. Reason: Bigger "pi"

10-15-2006 | 03:01 AM

TankerDriver

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Quote:

Originally Posted by tomgoodman

If it's not on the plate and you HAVE to calculate an arc segment length, it's 2 x "pi" x R x D divided by 360, where R is the radius of the arc and D is the number of degrees between the starting and ending radials. For example, the 15 DME arc from the 080 to the 140 radial would be 2 x 2.14 x 15 x 60 divided by 360 = 10.7 miles.

Caution: It's been 40 years since I took trigonometry, and even if my answer is correct, giving it in an interview might sound the "nerd alert"!

I was never a trig fan, so I use the 60 to 1 rule, where at 60 DME, each radial is 1 mile apart. So at 15 DME, there are 4 radials per mile. If you're going from 360 to 180 on the 15 DME arc, it'd be 180/4 = 45 NM. I'm not quite sure I understand your equation above because I'm getting 15 NM for a 60 degree change on a 15 DME arc.