Originally Posted by UAL T38 Phlyer

Juice is correct.

From an engineering standpoint, "power," = Force x Velocity. The traditional method to rate this in the US is Horsepower, which is 550 ft-lbs/second.

It's been a while since I've flown a turboprop, and I don't know the particulars of your engine, but here's a hypothetical example:

Torque: 1800 ft-lbs
RPM: 2400
"Average" Prop radius (To calculate average "speed" of the blade): 4 ft

Math:

1800 ft-lbs x 2400 rpm x 4 ft / 60 sec per minute (to convert RPM to RPS); then /550 to change ft-lbs/sec to horsepower

Answer: 523 hp.

How the engine develops that torque or rpm is irrelevant. Doesn't matter if the ITT split is 100 degrees: power is determined by ft-lbs/sec.

A way to prove it: if your turn coordinator is sensitive enough, the ball will move towards the higher-powered engine if the guy is matching ITT. ("Step on the good engine;" just like in engine-out practice)